高校物理 力学 ~ 運動量と力積
運動量 (momentum)
$$
\vec{p} = m \vec{p}
$$
\vec{p} = m \vec{p}
$$
\vec{p} = m \vec{p}
運動量の変化と力積
\begin{eqnarray*}
\Delta p = m v’ – mv = F \Delta t \\
\\
\Delta \vec{p} = m \vec{v}’ – m \vec{v} = \vec{F} \Delta t
\end{eqnarray*}
\Delta p = m v’ – mv = F \Delta t \\
\\
\Delta \vec{p} = m \vec{v}’ – m \vec{v} = \vec{F} \Delta t
\end{eqnarray*}
\Delta p = m v’ – mv = F \Delta t
\Delta \vec{p} = m \vec{v}’ – m \vec{v} = \vec{F} \Delta t
運動量保存の法則 (momentum conservation law)
\begin{eqnarray*}
m_1 v_1 + m_2 v_2 = m_1 v_1′ + m_2 v_2′ \\
\\
m_1 \vec{v}_1 + m_2 \vec{v}_2 = m_1 \vec{v}_1′ + m_2 \vec{v}_2′
\end{eqnarray*}
m_1 v_1 + m_2 v_2 = m_1 v_1′ + m_2 v_2′ \\
\\
m_1 \vec{v}_1 + m_2 \vec{v}_2 = m_1 \vec{v}_1′ + m_2 \vec{v}_2′
\end{eqnarray*}
m_1 v_1 + m_2 v_2 = m_1 v_1′ + m_2 v_2′
m_1 \vec{v}_1 + m_2 \vec{v}_2 = m_1 \vec{v}_1′ + m_2 \vec{v}_2′
反発係数 (coefficient of restitution)
\begin{eqnarray*}
e &=& \frac{|v’|}{|v|} = – \frac{v’}{v} \\
\\
e &=& \frac{|v_1′ – v_2’|}{|v_1 – v_2|} = – \frac{v_1′ – v_2′}{v_1 – v_2}
\end{eqnarray*}
e &=& \frac{|v’|}{|v|} = – \frac{v’}{v} \\
\\
e &=& \frac{|v_1′ – v_2’|}{|v_1 – v_2|} = – \frac{v_1′ – v_2′}{v_1 – v_2}
\end{eqnarray*}
e = \frac{|v’|}{|v|} = – \frac{v’}{v}
e = \frac{|v_1′ – v_2’|}{|v_1 – v_2|} = – \frac{v_1′ – v_2′}{v_1 – v_2}